Betting System Myths

Betting Both Sides: Why Hedging Does Not Remove the Edge

Simple roulette arithmetic shows that covering opposing outcomes does not escape the house edge. It locks in the cost of the edge on money that cancels out.

On this page
  1. The short version, and a caution
  2. The idea behind hedging
  3. A worked example on a single-zero wheel
  4. Where the cost went
  5. Uneven hedges
  6. A double-zero wheel
  7. Other tables, same logic
  8. Promotions and covering outcomes
  9. What hedging does do

The short version, and a caution

Casino games are games of chance with a built-in house edge. No strategy, system, pattern or timing changes the odds in the player’s favor over time, and most players lose money over time. Nobody should gamble money they cannot afford to lose. Betting on both sides of a game is sometimes presented as a way to cut risk, and it does reduce swings, but it does not turn an unfavorable game into a fair one.

The idea behind hedging

In finance and sports betting, hedging means taking a second position that offsets the first. If one position loses, the other gains, so the combined result is more stable. At a casino table the idea looks tempting: if red and black are opposite outcomes, why not bet on both and never lose?

The flaw is that the two outcomes are not the only ones. On a roulette wheel there is also the zero, which makes both bets lose together.

A worked example on a single-zero wheel

A single-zero wheel has 37 pockets: 18 red, 18 black and one green zero. Suppose, hypothetically, a player places $10 on red and $10 on black on the same spin. Both bets pay even money.

  • A red number comes up (18 of 37 pockets): the red bet wins $10 and the black bet loses $10. The net result is $0.
  • A black number comes up (18 of 37 pockets): the same thing in reverse, with a net result of $0.
  • The zero comes up (1 of 37 pockets): both bets lose, a net result of −$20.

The expected result is:

(36 × $0 + 1 × (−$20)) ÷ 37 = −$20 ÷ 37 ≈ −$0.54

The total wagered was $20, and 1/37 of $20 is about $0.54. So the expected loss is exactly the usual edge on the total amount staked. Nothing was saved. The player put $20 on the table and, in 36 spins out of 37, got the same $20 back.

Where the cost went

The wager that cancels out still counts as money wagered, and the edge applies to it. The player is paying about 2.7 percent on money that cannot win anything. That is arguably worse than a single $10 bet, which has an expected loss of about $0.27 and a real chance of winning $10. The hedge doubles the expected cost and removes the possibility of a win.

The result also looks different from the one the hedger imagined. Most spins feel like nothing happened, and occasionally there is a loss of $20. The edge has not gone away; it has been repackaged into a rare, larger loss.

Uneven hedges

What if the two bets are not the same size? Say a player puts $20 on red and $10 on black:

  • A red number: +$20 − $10 = +$10
  • A black number: −$20 + $10 = −$10
  • The zero: −$30

The expected result is (18 × $10 + 18 × (−$10) + 1 × (−$30)) ÷ 37 = −$30 ÷ 37 ≈ −$0.81. That is 1/37 of the $30 wagered. Again the expected loss equals the edge times the total staked, regardless of how it is split. This is the same principle that applies to every betting system: the average cost depends on the total wagered, not on how the bets are arranged.

A double-zero wheel

A double-zero wheel has 38 pockets, with 18 red, 18 black and two zeros. The same hypothetical $10 on each color loses $20 whenever either zero appears. The chance is 2 in 38, so the expected result is −$20 × 2 ÷ 38 = −$40 ÷ 38 ≈ −$1.05, which is about 5.26 percent of the $20 wagered. The extra zero doubles the cost of the same pattern.

Other tables, same logic

The reasoning carries over to other games. In baccarat, the player and banker bets are close to opposites, but each carries its own cost. Winning banker bets are usually subject to a commission, and a tie typically returns both main bets without a result. Placing baccarat bets on both sides pays the cost on each and leaves little to show for it. Bets that look like opposites at a craps table work similarly, in that the rules are written so that the edge survives on both sides. It is not an accident that the rules handle the one outcome that breaks the symmetry; those rules are where the edge lives.

The same applies to any attempt to cover many outcomes at once on a roulette layout. Covering more of the wheel increases the number of pockets that pay something, but the payouts are reduced in proportion, and the roulette edge stays the same.

Promotions and covering outcomes

Some players think covering opposing outcomes might help them clear a promotion’s playthrough requirement cheaply. That is not a loophole. Bonus terms typically restrict this kind of play, and the casino may treat it as bonus abuse, which can lead to voided winnings or a closed account. Even without the restriction, the hedge still costs the edge on every spin, so it does not escape the expected cost described above.

What hedging does do

Hedging reduces variance in the short term. A player who covers both colors will see far fewer wins and losses per spin. That can feel safer, and for some people it is a way to make a limited budget last longer. But a budget lasts longer only because little is at risk on each spin, and the expected loss per dollar wagered is unchanged.

If you find that you are using a pattern of bets to try to avoid losing, it can help to step back and ask what the money is for. Playing for entertainment with a fixed amount you can afford to lose is a clearer approach than trying to find a combination that cannot lose, because no such combination exists. Anyone worried about their gambling can contact a local support service.

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